(notice the word 'jokes' in the URL, but it's pretty well done)
> Each ounce of beer contains 16 latent calories, but extracts 1,036 calories (6,216 cal. per 6 oz. portion) in the temperature normalizing process.
I think it's muddling food calories (which are really mislabelled kilocalories) and temperature calories (which aren't). So that 16 should be 16000.
This is why you do this in joules!
(notice the word 'jokes' in the URL, but it's pretty well done)