So I suppose if you ever find a cycle where the full cycle has no all-even membe... | Hacker News

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Retr0id 45 days ago | parent | context | favorite | on: Powers of 2 with all even digits

So I suppose if you ever find a cycle where the full cycle has no all-even members, you can prove that there are no more all-even numbers to find.

sebzim4500 45 days ago [–]

That's not possible, at minimum 2,4,8,64,2048 would all be the the cycle for `k >= 4`.

Retr0id 45 days ago | [–]

I don't follow

sebzim4500 45 days ago | | [–]

Looking back I don't know what I was thinking ignore me.

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