The tutorial examples are run as part of the test suite. The tutorial example in...

drbawb · on April 3, 2013

Whoops, I did botch up the syntax on my listed example.

I compiled release-0.6; and sure enough `let numbers: [int, ..3] = [1,2,3];` compiles.

`let numbers: ~[int, ..3] = ~[1,2,3];` does not compile on my system though. Ditto for the @ sigil.

(Expected `~[int * 3] but found ~[<VI2>]`)

My understanding is that the first example [from the docs] allocates the vector on the stack.

My uncompilable examples should be equivalent except that they use the heap for storage.

Is there a reason this shouldn't compile?

Thanks so much for the reply!

sophiebits · on April 3, 2013

In fact you just want:

    let numbers: ~[int] = ~[1,2,3];

When you allocate a vector on the heap, you don't need to specify the size.

drbawb · on April 3, 2013

I was thinking you might have a function that operates on some fixed length vector.

For e.g: `fn foo(bar: ~[int, ..3]) { ... }`, and the compiler would enforce that you only pass vectors of length 3 to that function.

But since I can't get `~[int, ..3] = ~[1,2,3]` (etc.) to compile that seems to be impossible w/ vectors on the heap?

pcwalton · on April 4, 2013

It's a bug. Sorry about that. For now, write the type as `~([int, ..3])`.

sophiebits · on April 4, 2013

I stand corrected -- thanks, didn't realize that you could have a pointer to a fixed-length vector.

sophiebits · on April 3, 2013

I believe you can't do that. You can, however, make a function that only operates on 3-tuples:

fn foo(bar: (int, int, int)) { ... }