This text is part of:
[45]
The Conservatives had a majority of twenty-nine; but Kellogg's illegal Returning Board has continued to sweep away this Conservative majority of twenty-nine.
The figures, as manipulated by the rump of four members, are:
Fifty-three Republicans.
Fifty-three Conservatives.
Five cases referred.
One hit is scored by Kellogg.
If pretexts can be found for shutting out the five members, four of whom are Conservatives, neither side will have a legal quorum, and the Conservatives will not be able to carry a party vote.
In free popular assemblies the candidates usually sit and vote until their cases have been heard; but Kellogg thinks that rules which govern free assemblies everywhere else may be defied in New Orleans.
If these five members take their seats on the opening day, the Conservatives will have a legal quorum of fifty-six, and a sure majority of three, a probable majority of five.
What is to prevent that sure Conservative majority from indicting and deposing Kellogg, as Governor Warmoth was indicted and deposed?
A House in which neither party counts a
This work is licensed under a
Creative Commons Attribution-ShareAlike 3.0 United States License.
An XML version of this text is available for download, with the additional restriction that you offer Perseus any modifications you make. Perseus provides credit for all accepted changes, storing new additions in a versioning system.